10 Hard-to-Solve Riddles from the 18th Century



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We may think we’re way smarter than people of 300 years ago, being able to find almost any information in a matter of moments. But how will we get on without the Internet? Some of these riddles posed a real challenge to us. Check them out for yourselves!
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Fahad Hameed

Fahad Hashmi is one of the known Software Engineer and blogger likes to blog about design resources. He is passionate about collecting the awe-inspiring design tools, to help designers.He blogs only for Designers & Photographers.

44 thoughts on “10 Hard-to-Solve Riddles from the 18th Century

  • September 10, 2017 at 1:23 pm
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    The one with the leap year can't be from the 18th century. The 1700's only had 24 leap years instead of four as neither the year 1700 nor 1800 were leap years. The definition says a year is a leap year if the number of the year is divisible by four UNLESS it's divisible by 100 UNLESS it's divisible by 400. So 1600 and 2000 are leap years, but 1700, 1800 (and 1900) are not.

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  • September 10, 2017 at 1:23 pm
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    …..algebra type ?'s reminds me of the 8th grade and gives me the heebie-jeebies…..please pass me the Pepto Bismol and Maalox in mass quantities…….

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  • September 10, 2017 at 1:23 pm
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    #2 doesnt make sence the answer is supossed to be 2 and 6
    if person A has 6 and person B has 2 that means if person A gave B 2 they would both have 4 and if person B gave person A 2 plums then person A would have twice as many as person B, they didnt even solve it right

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  • September 10, 2017 at 1:23 pm
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    #5 is wrong. A man with his father and grandfather are 2 fathers and 3 sons. Just because your father is not with you doesn't mean you are not a son.

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  • September 10, 2017 at 1:23 pm
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    #2 Should be reworded. "If the second gives the other 2 plums, he'll have twice as many" can be interpreted as x +2 =2x
    Instead, you should say "If the second gives the other 2 plums, he'll have twice as many as them." Which must be interpreted as intended (x+2=2y)

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  • September 10, 2017 at 1:23 pm
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    the solution is not correct in #10… it says there that 4 times the lesser part is equal to 3 times the larger part and we know perfectly well that 10×4 is not equal to 120×3, not even close..10×4=120/3, but this was not what the question (in this case riddle) asked..

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  • September 10, 2017 at 1:23 pm
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    Just like the one that appeared to copy this a few days later, for #10 the larger group should be 1/3 of 4 times the smaller group, not 3 times it. Wording means everything in word problems.

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  • September 10, 2017 at 1:23 pm
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    Question 9 is written incorrectly – it needs to read: "…4 times the lesser part would equal one third of Larger part", because 10*4 = 40 and 120/3 = 40 also
    121,111 does not consist of 11 digits – something like 12,123,123,123 does. 121,111 consists of SIX digits
    These two are not really fair given poor writing and diction. The rest are ok.

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  • September 10, 2017 at 1:23 pm
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    Riddle ten is incorrect. Apply the original question parameters to his numbers. His numbers are wrong because his starting equation DIVIDED by 3 om the right hand side instead of multiplying by three. Make this correction and the answer is 55 5/7ths nuts on one side and 74 2/7ths nuts on the other. When latter side is multiplied by 3 and the other by 4, we get an equation that works.

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  • September 10, 2017 at 1:23 pm
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    Who noticed that the title says ten riddles and theres eleven riddles in total? ('_')

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  • September 10, 2017 at 1:23 pm
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    Im afraid 4 times 10 does not equal 3 times 120
    I cant believe i even watched any of this
    I should have known there was a problem when 390 was not divisible by seven but still i kept watching

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  • September 10, 2017 at 1:23 pm
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    3x=4y ==> x=4y/3
    This video's answers for no. 10 were: x=120 and y=10.
    Test: x=4y/3 ==> 120=4*10/3 ==> 120=40/3 ==> 120*3=40 ==> 360=40 ==> INSTAFAIL

    Here's a Problem:
    ________________
    Find x and y, supposing that 3x=4y.

    *Use this: x>y and x+y=130
    3x=4y ==> x/4=y/3.
    **Test your hypothetic guess numbers with one of the following:
    a) x=4y/3, or
    b) y=3x/y

    Reply
  • September 10, 2017 at 1:23 pm
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    #10, it says the answer is 10 and 120 nuts, but how can that be? It states in the riddle that "4 times the lesser part would equal 3 times the larger part"… 4(10) does not equal 3(120). The answer given would need the wording to be "4 times the lesser part times 3 would equal the larger part"

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  • September 10, 2017 at 1:23 pm
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    surely if you are puttin one sack inside the other u are only filling one sack?

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  • September 10, 2017 at 1:23 pm
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    The music is so lame, and they get their own riddles wrong, frankly if this is the 'bright side' of the ones making this video, I rather avoid their 'dark side' altogether… you sure look dumb when your answer is right but just for ANOTHER QUESTION…

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  • September 10, 2017 at 1:23 pm
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    I thought with the matchsticks it was only two. One on top and one on the bottom, so I thought it'd be smart to move the bottom one 45 degrees as it'll make the shape of a box. Also why is the thumbnail at the end of the video. What a sneaky thing to do luckily I can fast forward all this tomfoolery haha!

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  • September 10, 2017 at 1:23 pm
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    Half of them do to wording are false the maker of this video obviously cant solve them either so i ask what was the point of this

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  • September 10, 2017 at 1:23 pm
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    I only guess question #7, #9, #11, that's not much but at least is something. I found one question extremely annoying because I didn't get it at all and that's question #8.

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  • September 10, 2017 at 1:23 pm
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    could also have age for boy as 4.75 +4.75+0.5+10. You said add a half not add half of his age.
    for birds, 5 birds and 4 trees also works, if not compelled to have 2 in each tree.
    for the nuts, last time i checked, 4 times 10 is 40, and 3 times 120 is 360. Your sums are wrong. did you mean somethings else and worded it wrong? how about 55.714 and 74.286: 3 times 55.714 =222.856, 74.286 times 4=222.858

    Reply

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